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(y+2)^2+(y-1)^2=5(2y+3)
We move all terms to the left:
(y+2)^2+(y-1)^2-(5(2y+3))=0
We calculate terms in parentheses: -(5(2y+3)), so:We get rid of parentheses
5(2y+3)
We multiply parentheses
10y+15
Back to the equation:
-(10y+15)
(y+2)^2+(y-1)^2-10y-15=0
We add all the numbers together, and all the variables
-10y+(y+2)^2+(y-1)^2-15=0
We move all terms containing y to the left, all other terms to the right
-10y+(y+2)^2+(y-1)^2=15
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